How to get a 12 volt Power Supply using 7805

This 12 volt power supply using 7805 circuit is simple and useful. Sometimes we need to get 12 VDC, but we only have 5 or 9 volts regulators (7805, 7809).

This voltage regulator looks like fixed regulators we already know but with the difference that it have two additional resistors (R1 and R2) (see the diagram).

These two resistors are used to establish a voltage divider, which puts a non zero voltaje on the COMMON (ADJ) pin of the 7805 regulator.

Calculating the voltage on the COMMON pin (now ADJ) of 7805, we get 7.2 volts. There are 7.2 volts across the 180 ohm resistor (R2) and 4.8 volts across the 120 ohm resistor (R1).

From the above it follows that the 180 ohm resistor serves to increase the voltage at the COMMON pin. If we want to get a different voltage, we just have to change the value of the resistors. Notes:

• We change the name of the 7805 COMMON pin by the name ADJ because, the voltage on this pin can be changed using external resistors.
• The voltage between the Output pin and the ADJ pin of the regulator, must be maintained at 5 volts (4.8 volts in our case).
• The LM7805 integrated circuit must use a heatsink to prevent damage LM7805 voltage regulator Pinout

List of components for 12 volt power supply using 7805 circuit

• 1  diode bridge (DB)
• 1  7805 voltage regulator IC
• 1  120 ohms resistor, 1/4 watt  (R1)
• 1  180 ohms resistor, 1/4 watt (R2)
• 1  220 ohms resistor, 1/4 watt (R3)
• 1  2200 uF, (microfarads) 50 volts  electrolytic capacitor (C1)
• 1  10 uF, 25 volts electrolytic capacitor (C2)
• 1  red LED (D)
• 1  220/110VAC to 16VAC (not shown on the diagram) transformer to be connected to the diode bridge
• 1  heatsink for the LM7805 IC
• 5
•
•
•
•
•
•
•
•
5
Shares
•
5
Shares
• 5
•
•
•
•
•
•
•
Tagged with: